TITRATION OF AN ACID (A PREPARED STANDARD SOLUTION OF KH?O?C?) AGAINST A BASE (NAOH) USING PHENOLPHTHALEIN AS AN INDICATOR BY GRACE The aim of this experiment is to fake a well-worn solution of potassium hydrogen phthalate (KH?O?C?) and there bowknot use it to calculate the submerging of atomic pattern 11 hydroxide by titrating the dit (KH?O?C?) against the fore (NaOH). Before the whole experiment could take place, some apparatus were needed which included the following; A weighing balance, burette, pipette, a conical flask, clamp and then the setup was as to a lower place; THEORY To calculate for the moles of KH?O?C?, I utilize n (mol) =m (g)/M (gmol?? (JOHN discolor AND SADRU DAMJI, PG 6 OF CHAPTER 1.THIRD EDITION). Whereby m= muss of the sulfurous, M=molar tummy of the acid and n= twist of moles. Molar mass of KH?O?C? is 204.1g/mol and its mass is 1g wherefore=1g/204.1gmol?? n=0.0 048996mol notwithstanding more, to calculate for the immersion of the acid, I utilize C(moldm?3.) =n (mol)/v (dm3) Whereby c= stringency, n=number of moles and v=volume use. (JOHN park AND SADRU DAMJI, PG 27.THIRD EDITION) Volume=0.1dm3 Concentration of acid =0.0048996mol/0.1dm3 =0.
049moldm?3 Also, to calculate for the amount titre volume of the acid used, I summed up the ternion consistent values from my experiment and separate it by 3(sarps series, 2009) so Average Titre volume= (19.60+19.60+19.60) 3 =19.60cm3 Also, to calculate for the conce! ntration of sodium hydroxide, I used The dilution factor, C?v?=C?v? (JOHN GREEN AND SADRU DAMJI pg28, third edition) whereby C?=concentration of the acid used=0.049moldm?3 v?=volume of acid used (titre volume) =19.60cm3 C?=concentration of the base, v?=volume of the base used=10cm3 Therefore C?= (0.049*19.60)/10 C?=0.096 moldm?3 Therefore the concentration of sodium hydroxide is0.096 moldm?3 |Burette...If you want to slipperiness up a full essay, order it on our website: OrderCustomPaper.com
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